Question

A father is three times as old as his son. After 12 years, he will be twice as old as his son. Find the present ages of the father and the son.

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The present ages is Son and Father are 12 and 36 respectively.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Father is = three times as old as his son

After 12 Years = he will be twice as old as his son.

To Find :

Their present ages

Solution :

Consider the present ages of -

• Son as x
• Father as 3x

Ages after 12 Years -

• Father = (3x + 12)
• Son = (x + 12)

According to the Question -

After 12 years, Father's age = Twice the age of Son

★ $\boxed{\sf{(3x+12)=2(x+12)}}$

$\longrightarrow$ (3x + 12) = 2(x + 12)

$\longrightarrow$ 3x + 12 = 2x + 24

$\longrightarrow$ 3x - 2x = 24 - 12

$\longrightarrow$ x = 12

Son's present age is 12 years

$\rule{300}{1.5}$

★ Value of 3x

$\longrightarrow$ 3 × 12

$\longrightarrow$ 36

Father's age is 36 years.

$\therefore$ The present ages is Son and Father are 12 and 36 respectively.

Answer 2

Answer:

father3x years, Son x years now

3x+12=2(x+12)

3x+12=2x+24

3x-2x=24-12

X = 12

3 x = 36

son12years and father 36 yrs