Question

A father is three times as old as his son after 5years his age will be two and half time as old as his son .Represent the siruation as pair of linear equation in two variables and find their ages​

Answer 1

Answer:

Answer: 15 years and 45 years.

Step-by-step explanation:

let the age of son = x

so the age of father = 3x

according to question after 5 years

3x+5=

2

5

∗(x+5)

6x+10=5x+25

x=15

so the age of son is 15 years and age of father is 45 years

hope it helps

Answer 2

Answer:

after 5 years son's age =20,fathers age is 50 which is 30 years more than son's age.

Step-by-step explanation:

Let the son's age be x.

Father's age =3x

∴3x−5=4(x−5)

or 3x−5=4x−20

or 20−5=4x−3x or x=15

After 5 years, son's age is x+5=15+5=20.

Father's age is 3x+5=45+5=50 which is 30 years more than son's age.