Question

A father is three times as old as his son After twelve years his age will be twice as that of his son then. Find their parents age

Answer 1

after twelve years, his age will be twice as that of his son then. find their present ages.
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Equations:
f = 3s
f+12 = 2(s+12)
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Substitute for "f" and solve for "s":
3s+12 = 2s+24
s = 12 yrs (the son's age)
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Solve for "f":
f = 3s
f = 3*12 = 36 yrs (the father's age)

Answer 2

Heya !!!



Let present age of son be X years.



Then the age of father = 3X years.





After 12 years age of son = ( X +12)




After 12 years age of father = ( 3X + 12)




According to question,



Age of father after 12 years = 2 ( Age of son after 12 years)



3X + 12 = 2 ( X + 12)



3X + 12 = 2X + 24



3X - 2X = 24-12




X = 12




Age of son = X = 12 years



and,



Age or father = 3X = 3×12 = 36 years.




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