Math, asked by vaishnavikelkar19949, 3 months ago

A father is three times as old as his
son. Find the present ages of father and the son.
Father's age is three times the sum of ages of his two children. After 5 years his age will
be twice the sum of ages of two children. Find the age of father.
idec his son Two years later, his ac
[CBSE 2003, 2019​

Answers

Answered by nehalpatel28
1

Answer:

Let the age of father =x years

The sum of the age of 2 children =y years

According to the first condition

⇒x=3y

After 5 years

⇒ Father's age =x+5

⇒ The sum of ages of his two children =y+10

According to the second condition

⇒x+5=2(y+10)⇒x+5=2y+20

⇒x−2y=15

Put the value of x from eq1

⇒3y−2y=15⇒y=15

Put y=15 in eq1

⇒x=3×15⇒x=45

Hence, father age =45 years

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