A Father is three times as old as his son. In 10 years, he will twice as old as his son. How old is the father at present?
Answers
Answer:
Step-by-step explanation:
Let son's present age be: x so, Father's present age : 3x After 10 years: Son's age = x+10, Father's age = 3x+10 According to the question, we have: 3x+10 = 2*(x+10) + 5 solving it, we get: x=15 Hence, Present age of son = x =15 years and Present age of father = 3x = 45 years.
Answer:
here the answer
Step-by-step explanation:
A father is three times old as his son. In 10 years time, he will be double his son's age. What are their present ages?
Not sure what the ratio method is, but if you set the father’s age as y and the son’s age as x then you can write the equations y= 3x (bc the father is currently three times as old as the son) and y+10=2(x+10) (bc in ten years the father will be twice as old as the son). If you swap the Y in the second equation with 3x (bc as we proved in the first equation 3x=y) and distribute the 2 to the x and the 10 you get 3x+10=2x+20. Now subtract 10 from both side and 2x from both sides and you get x=10. Plug 10 in for x in the first equation (y=3x) and you get y=30. So now you know the son is 10 and the father is 30.
⁰ What is the present age of the father and son?
The age of the father is 3 times the age of his son. Ten years before, the age of the father is 5 times the age of his son. What are their present ages?
X= 3y= 30.
Father’s age is 30 and son’s age is 10.
Thank u.
Present age
Son=x
Father =3x
After 10 years, ages will become
Son =x+10
Father =3x+10
By given condition
3x+10 =2 (x+10)
3x+10 =2x+20
3x_2x=20_10
x=10
Son’s age =x=10
Father's age =3x=3*10=30
Let say:
F= Father’s age
S = Son's age
For (Eq1) Father is three times as old as his son:
F = 3S
For (Eq2) In 10 year time the Father age will be twice as old as his son:
F + 10 = 2(S + 10)
F=2S+20–10
F=2S+10 (Eq2)
Then, lets us substitute the (Eq1) into the (Eq2)
3S=2S+10
3S-2S=10
S=10
Then son is 10 years old.
and Father
F=3S so 3 x 10
.