Question

A father is three times as old as his son .in 10 years time his age will be double his son's age.Find their present age​

Answer 1

Answer:

10 years and 30 years respectively of son and his father.

Step-by-step explanation:

Present age:

Let the age of the son be n

Age of father =3n

Age after 10 years:

Age of his son=n+10

Age of father=3n+10. or. 2(n+10)

Therefore,

3n+10=2(n+10)

3n+10=2n+20

3n-2n=20-10

n=10

Present age of son=10 years

Present age of his father =10x3 years

=30 years

Answer 2

Age of Father = 30

Age of Son= 20

Step-by-step explanation:

3x+10=2x

x=10