Question

A father is three times as old as his son. In 10 years time he will be double his

son’s age. Find their present ages.

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Answer 1

Answer:

let child present age be x then father is 3x. after 10 years child will become x+10. and father 3x+10. but in question it is given he will be double. so 2(x+10) = 3x+10 Or 2x +20= 3x+10 or x= 10. chil at present is 10. father is 30.

Step-by-step explanation:

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Answer 2

Answer:

Answer:

it's

Step-by-step explanation:

equation will be like this

3x+10