Question

A father is three times as old as his son. In 12 Years time, he will be twice as old as his son. Find the percent ages of father and the son.​

Answer 1

Step-by-step explanation:

Let son's present age == S

Father's present age == 3 times son == 3 S

In 12 years,

Son's age == S + 12

Father's age == 3 S + 12

Given, at this time (12 years), father's age is twice son's age

3 S + 12 = 2*(S + 12)

3 S + 12 = 2 S + 24

3 S - 2 S = 24 - 12

S = 12

Present age:

Son's age == 12

Father's age == 36

Answer 2

Hope this will help you