A father is three times as old as his son. In 12 years time, he will be twice as old as his son. The sum of the present ages of the father and the son is: (ay (b) (c) (d) 36 years 48 years 60 years 42 years
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d) 36 year is the correct answer
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Consider the present age of son be x.
Consider the present age of father be y.
Given that father age is three times that of son.
That is, y = 3x
Also in 12 years time fathers age will be twice of the son's present age.
That is, y + 12 = 2 ( x + 12 )
Substitute y = 3x in the above equation.
3x + 12 = 2 (x + 12)
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
y = 3x = 3*12 = 36
Sum of the present ages of father and son = x + y = 12 + 36 = 48 years
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