Math, asked by Mitali240706, 6 months ago

a father is three times as old as his son. in 14 years' time, he will be twice as old as his son. how old is the father now?

Answers

Answered by SarcasticL0ve
28

A father is three times as old as his son. in 14 years time, he will be twice as old as his son.

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We have to find, Age of father.

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☯ Let Present age of son be x.

☯ Therefore, Present age of his father is 3x. \\ \\

\underline{\bigstar\:\boldsymbol{According\:to\: Question\::}}\\ \\

After 14 years he will be twice as old as his son. \\ \\

Therefore,

Their ages after 14 years, \\ \\

  • Age of son = x + 14
  • Age of father = 3x + 14 \\ \\

:\implies\sf 2(x + 14) = 3x + 14\\ \\

:\implies\sf 2x + 28 = 3x + 14\\ \\

:\implies\sf 2x - 3x = 14 - 28\\ \\

\qquad:\implies\sf - x = - 14\\ \\

\qquad:\implies{\boxed{\frak{\purple{x = 14}}}}\;\bigstar\\ \\

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Hence,

  • Age of son, x = 14 years

  • Age of his father, 3x = 3 × 14 = 42 years \\ \\

\therefore\;{\underline{\sf{Present\;age\;of\; father\;is\;\bf{42\;years}.}}}

Answered by RisaliPerera
0

Answer:

Step-by-step explanation:

It's much easier when you visualize the problem:

The father's age will be double the child's age in 14 years.
So, using the data below, we can make the equation:

3x + 14 = 2 (x + 14)
3x + 14 = 2x + 28
3x - 2x = 28 - 14
x = 14

So 3x:
3 x 14 = 42

The father is 42 years old and the child is 14 years old presently.



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