Math, asked by GreenTree, 11 months ago

A father is three times as old as his son. Six years ago he was five times as old as his son was. Find their present age.

Answers

Answered by superjunior
5

let their present ages be : x and 3x

ages before six years :--

son = x -6

father = 3x-6

father was five times the son

so,

ACCORDING TO QUESTION.

(X-6)5 = 3x-6

5x - 30 = 3x-6

5x - 3x = 30-6

2x = 24

X = 24/2

X = 12

age of son is 12 (X)

age of father is 36 (3x)

Answered by sanjaykumar1810
0

hey check the attachment....

son's age=12

father's age=3*x=3*12=36...

Attachments:
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