A father is three times as old as his son. Six years ago he was five times as old as his son was. Find their present age.
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Answered by
0
hey check the attachment....
son's age=12
father's age=3*x=3*12=36...
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Answered by
1
hey mate
(1) 3S = F
and six years ago they were
(2) 5*(S-6) = F-6
calculate 5*(S-6)
5S - 30 = F-6
Subtract left and right side by -F
Add 30 to left and right side
5S - F = 24
Put (2) 3S = F into the equation above
5S - 3S = 24
2S = 24
S = 12
insert result in (2) 3S = F
3*12 = F
36 = F
So the son is 12 years, and the father is 36 years.
I hope this helps
have a nice day
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