A father is three times as old as his son. Six years ago he was five times as old as his son was. Find their present age.
Answers
Answered by
13
Let the present age of son be x.
So, father's age =3x
Six years ago,
Son's age =x-6
Father's age = 3x-6
But A/Q
Father's age = 5× son's age
3x-6=5(x-6)
3x-6 =5x -30
-6 +30 =5x -3x
24 =2x
24/2 = x
12 = x
So, the present age of son = x =12 years
Father = 3x = 3×12
=36 years
So, father's age =3x
Six years ago,
Son's age =x-6
Father's age = 3x-6
But A/Q
Father's age = 5× son's age
3x-6=5(x-6)
3x-6 =5x -30
-6 +30 =5x -3x
24 =2x
24/2 = x
12 = x
So, the present age of son = x =12 years
Father = 3x = 3×12
=36 years
Answered by
0
hey check the attachment....
son's age=12
father's age=3*x=3*12=36...
Attachments:
Similar questions