Question

A father is three times as old as his son. Six years ago he was five times as old as his son was. Find their present age.

Answer 1

Answer:

Step-by-step explanation:

Let father =x

Son=y

X=3y [eq1]

6 years ago

X-6=5[y-6]

X-6=5y-30

X-5y=-24

Substitute (eq 1)

3y-5y=-24

Y=12

X=3(12)

X=36.

Answer 2

Answer:

Step-by-step explanation:

xf