Question

a father is thrice as old as his son 10 years ago he was five times as old as his son was then what are their present ages?​

Answer 1

Answer:

I am sure that the map is not good enough coins to get my hands off

Step-by-step explanation:

define the map and the world cup and the world cup is the best in the world cup and the world is a place to be a good start and we will be fun to play in our team and we have been very fast for the last three years and we are not playing against them but not a girl in a game like this is best map and we will have a good time to get a win one

Answer 2

Given:-

${\rm \red {A \: father \: is \: thrice \: as \: old \: as \: his \: son.}}$

${\rm \green {10 \: years \: ago, \: he \: was \: five \: times \: as \: old \: as \: his \: son.}}$

To Find:-

${\rm \pink{Their \: present \: ages.}}$

Solution:-

Let the present ages of the father and his son be x and y respectively.

According to the question,

${ \boxed{\rm \red {x \; = \; 3y}}}$ ---- (1)

10 years ago,

Age of father = x – 10

Age of son = y – 10

Therefore,

x – 10 = 5(y – 10)

x – 10 = 5y – 20

3y – 10 = 5y – 20 [ From equation(1), x = 3y ]

5y – 3y = – 10 + 20

2y = 10

${ \boxed{\rm \pink {y \; = \; 5}}}$

x = 3y

$\therefore$ x = 3 × 5 = 15 years

Therefore, present ages of father is = x = 15 years and present ages of son is = y = 5 years

$\bf{\rm \red {Present \: age \: of \: father \: is \: 15 \: years \: and \: present \: age \: of \: son \: is \: 5 \: years \: [Ans]}}$

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