Question

a father is twice as old as his daughter . if 20 years ago, the age of the father was 10 times the age of the daughter , what is the present age of the father?

Answer 1

Answer:

Father is 45 Years.. check the attachment... I have accidentally wrote 50 its 45

Answer 2

Given:

A father is twice as old as his daughter. 20 years ago, the age of the father was 10 times the age of the daughter.

To find:

The present age of the father.

Solution:

The present age of the father is 45 years.

To answer this question, we will follow the following steps:

Let the present age of the father be x years.

So,

according to the question,

The age of the daughter

$= \frac{x}{2} \: years$

20 years ago,

The age of the father = (x - 20) years.

The age of the daughter

$= ( \frac{x}{2} - 20) \: years$

So,

According to the question, we have,

20 years ago,

Age of father = 10 times age of daughter

$x - 20 = 10( \frac{x}{2} - 20)$

On solving the above, we get,

$x - 20 = 5x - 200$

$4x = 180$

$x = \frac{180}{4}$

$x = 45 \: years$

Hence, the age of the father is 45 years.