Question

a father is twice as old as his son .10 years ago ,he was five times as old as his son was then. what are their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Let son's age be x

Father's age= 2x

10 years ago= 2x-10

Son's age 10 years ago= x-10

Therefore,

2x-10= 5(x-10)

2x-10=5x-50

5x-2x=50-10

3x=40

x=40/3= 13.33

2x=40/3*2=80/3=26.66