Question

A father is twice as old as his son. 20 years ago the age of the father was 12 times the age of the son. the present age of the father is :

Answer 1

Let the present age of father be x
& son be y

according to question,
x=2y.....i

twenty years ago,
(x-20)=12(y-20)
x-20=12y-240
x-12y=-240+20
x-12y=-220............ii

putting the value of x in equation ii
x-12y=-220
2y-12y=-220
-10y=-220
y=22

putting value of y in equation i
x=2y
x=2×22
x=44

Father's present age is 44
& son's present age is 22

Answer 2

44 is Father's age and son 's age is 22