Question

a father is twice as old as his son. 20 years ago the age of the father was 12 times the age of the son. the present age of the father (in years) is

Answer 1

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

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Let the age of the son be = x
let the age of the father be = 2x

20 years ago ,

the age of the son is = x-20
and the age of the father is = 2x-20


( 2x-20 ) = 12 × ( x-20 )

( 2x-20 ) = ( 12x -240 )

2x = 12x - 240 + 20

2x = 12x-220

-10x= -220

-220 ÷ (-10 ) = 22


➡ SO THE PRESENT AGE OF THE SON IS = 22 years.

➡ THE PRESENT AGE OF THE FATHER IS = 2×22 = 44 years


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HOPE IT HELPS YOU.✌
THANKS.❤

Answer 2

Hola User!

Let us take the age of the son as ' x '

Father's age as ' 2x '

20 years ago :

Son = x - 20

Father = ( 2x - 20 )

Equation :

12 ( x - 20 ) = 2x - 20

12 x - 240 = 2x - 20

10 x = 220

x = 220 ÷ 10

x = 22

Son's present age = 22

Fathers = ( 2 x )

Father age = 44

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