Question

a father is twice as old as his son 20 years hence the father will be one one by two times as old as his son ,find their present age​

Answer 1

Answer:

Father's present age is 40 years, and his son's age is 20 years.

Step-by-step explanation:

Let's assume Father's age be "x", and Son's age be "y"

Currently, Father's age is 2 times of his Son, which is (x = 2y)

20 years later the equation will be  -

x+20 = 1.5(y+20)

Substitute value of x with 2y, then -

2y+20 = 1.5(y+20)

⇒ 2y+20 = 1.5y + 30

⇒ 0.5y =  10

⇒ y =  10/0.5 = 20 years

And, x= 2y, therefore x = 2*20 = 40 years

Hence, Father's present age is 40 years, and his son's age is 20 years.