Question

A father is twice as old as his son. If 20 years ago the age of father was 4 times the age of the son what is the present age of the father

Answer 1

Answer:

Present age of father is 60 years.

Step-by-step explanation:

Let age of son be x yrs.

Then, father's age = 2x yrs

ATQ= 2x-20 = 4(x-20)

= 2x-20= 4x-80

= 2x-4x=-80+20

=-2x=-60

Therefore, x= -60/-2=30

So son's age= 30 yrs

father's age=60 yrs