Question

A father is twice as old as his son. Ten years ago, the ratio of their ages was 5:2, what are their present ages?

Answer 1

Answer:

if the son’s age is x, the father’s age is 2x.

Ten years ago:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

2x = 48

So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to