A father is twice as old as his son.The sum of the ages is 99 years.Find their ages
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Answered by
2
let the son's age be x and father's age be y
2x = y
and , x+y = 99
now substituting 2x = y we get
x+2x = 99
3x = 99
x = 33
then y = 66
2x = y
and , x+y = 99
now substituting 2x = y we get
x+2x = 99
3x = 99
x = 33
then y = 66
Answered by
5
According to given sum,
Let age of son be x . then the fathers ages will be 2x .
And sum of ages =99
x+2x=99
3x=99
x=33
Hence the age of son is 33 & age of father is 66 .
:-)hope it helps u.
Let age of son be x . then the fathers ages will be 2x .
And sum of ages =99
x+2x=99
3x=99
x=33
Hence the age of son is 33 & age of father is 66 .
:-)hope it helps u.
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