Question

a father is two times as old as his son 16 years ago the age of the father was three times the age of his son what is the present age of the father​

Answer 1

Answer:

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Answer 2

Answer:

let the father s age =x

let the son age =y

x=2y........(1.)

16 years ago

age of father=(x-16)

age of son=(y-16)

A.T.Q

x-16=3(y-16)

x-16=3y-48

x-3y=-48+16

x-3y=-32.....(2.)

put the value of x

2y-3y=-32

-y=-32

y=32

put the value of y in eq. 1

x=2y

x=2×32

x=64

so the present age of father is 64 years.