Question

A father's age is 3 times of his son.After 12 years father's age will be twice that of the son. Find their present ages.
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Answer 1

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Answer 2

ANSWER

Let’s assume the present ages of the father as x years and that of his son’s age as y years.

From the question it’s given that,

Father is 3 times as old as his son. (Present)

So, the equation formed is

x = 3y

⇒ x – 3y = 0……. (i)

Also again from the question it’s given as,

After 12 years, father’s age will be (x + 12) years and son’s age will be (y + 12) years.

Furthermore, the relation between their ages after 12 years is given below

x + 12 = 2(y + 12)

⇒ x + 12 = 2y + 24

⇒ x – 2y – 12 = 0…… (ii)

Solving (i) and (ii), we get the solution

By using cross-multiplication, we have

(VIEW IN IMAGE)

x = 36, y = 12

Hence, the present age of father is 36 years and the present age of son is 12 years.