Question

A father's age is 3 times the sum of ages of his two sons. Five years later he will be the twice of the sum of ages of his two sums.the the present age of the father?

Answer 1

Answer:

45 years

Step-by-step explanation:

Let father's age be F.

Let sum of his both son's ages be S.

According to question,

F=3S     .......(1)

Also, F+5=2(S+5+5)

=>F+5=2S+20

=>F=2S+15    ......(2)

Putting value of F from (1) in (2), we get,

=>3S=2S+15

=>S=15

So, from (1), we get

F=3S=3 x 15 = 45 years

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