Question

A father's age is 3 times the sum of ages of his two sons. Five years later he will be twice the sum of ages of his two sons. Find the present age of the father.

please answer this in one variable ​

Answer 1

Answer:

Let the age of father be x years and sum of the ages of his children by y years.

After 5 years,

Father's age = (x + 5) years

Sum of ages of his children = (y + 10) years

From the given information, we have:

x = 3y ...(1)

and x + 5 = 2(y + 10)

x - 2y = 15 ...(2)

From (1) and (2), we have,

3y - 2y = 15 y = 15

x = 3y = 45

Father's age = 45 years

Answered by | 26th Jul, 2017, 12:26: PM

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Answer 2

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