Question

A father's age is 3 times the sum of ages of his two sons. Five years later he will be twice the sum of ages of his two sons. Find the present age of the father. pls tell with proof only. don't spam here.​

Answer 1

Answer:

Let the sum of Age of sons be x

age of father be 3x

According to question:-

3x+5=2(x+5)

3x+5=2x+10

3x-2x=10-5

x=5

Present Age of father=5(3)

=15 years

Verification:-

3(5)+5=2(5+5)

15+5=2(10)

20=20

Since,LHS=RHS

Hence,proved.

Note: This question in real life is not possible.

Answer 2

Hi  Mate :)

Here's your Answer:-

Answer : Let the age of the sons be x and y.

Given that Father’s age is three times the age of his two sons.

Therefore, present age of father is 3(x+y)

Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

Therefore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

3(x+y)+5 = 2(x+5+y+5)

=> 3x+3y+5 = 2x+10+2y+10

=> 3x+3y+5 = 2x+2y+20

=> -2x+3y-2y = 20–5

=> x+y = 15

Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

Thus the age of the father is 45.

Have a nice Day <3

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