a father's age is 3 times the sum of Ages of his two sons. 5 years later he will be twice the sum of Ages of his two sons. find the present age of the father
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Let the present age of father be x. And sum of ages os sons be 'a'.
Then,
x = 3a
x+5 = 2(a+10)
x+5 = 2(x/3 + 10)
3x + 15 = 2x + 60
Therefore, x = 45
i.e, at present, father is 45 years old.
Hope this helps!
Then,
x = 3a
x+5 = 2(a+10)
x+5 = 2(x/3 + 10)
3x + 15 = 2x + 60
Therefore, x = 45
i.e, at present, father is 45 years old.
Hope this helps!
Answered by
1
Here's the answer. please inform me if it is incorrect.
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Manasrrrr:
It's incorrect.
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