Question

A father's age is 3 times the sum of ages of his two sons . Five years later he will be twice the sum of ages of his two sons . Find the present age of the father .

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Answer 1

his present age is 72 years

Answer 2

Hi guys

one son age be= x

Second son age be = y

Father's present age=3(x+y)

After 5 yrs:

First son age= x+5

Second son age= y+5

Father's age =2(x+5 + y+5)

But at the same time father'sage will also be= (present age + 5 yrs )

=(3(x+y) + 5)

=3(x+y) + 5

= 2(x+5 + y+5)

3(x+y) -2(x+y)= 15

(x+y) = 15

Now father's present age= 3(x+y)

=3×15

= 45 yrs

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