Math, asked by soundaryasmiley31, 2 months ago

a father's age is 30 years older than his son in two years his age will be twice the age of his son the present age of father is​

Answers

Answered by shubhamambi9533
2

Answer:

28 & 58

Step-by-step explanation:

a father's age is 30 years older than his son in two years his age will be twice the age of his son

the present age of father is 58

Answered by qwwestham
0

The present age of the father is 58 years.

Given,

Father is 30 years older than his son,

Father's age after 2 years will be twice his son's age.

To find,

Father's present age.

Solution,

Firstly, let the father's present age be f years, and the son's present age be s years.

Now, the father is 30 years older than his son. So,

f=s+30     ...(1)

After 2 years,

father's age will be f+2 years, and,

son's age will be s+2 years,

It is given that after 2 years, the father's age will be twice the son's age. So,

f+2=2(s+2)     ...(2)

From equation (1), we have,

s=f-30

Substituting this value in equation (2), we get,

f+2=2((f-30)+2)

Simplifying the above equation,

f+2=2(f-28)

\implies f+2=2f-56

\implies f+2=2f-56

\implies 56+2=2f-f

Rearranging,

f=58

Father's present age is = 58 years.

Therefore, the present age of the father is 58 years.

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