A father's age is four times that of his son. After 5 years, it will be three times that of his son. How many more years will take if father's age is to be twice that of his son?
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let the present age of son be x.
so father's age = 4x
after 5 yrs,
4x+5=3(x+5)
4x+5=3x+15
4x-3x=15-5
x = 10
son 's present age =10
father's present age = 4*10=40
suppose after z yrs, father's age will be twice of son's age
so
40+z = 2(10+z)
40+z = 20+2z
z= 20
anseer is 20 yrs
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