Question

A Father's age is four times that of his son . Before 8 years the father's age was sixteen times that of his son . find their present ages .​

Answer 1

Answer:

Let son's present age be x and fathers present age be 4x

8 yrs ago:

Son's age = x - 8

Fathers age = 4x-8

Also, Fathers age = 16(x-8)

4x -8 = 16x - 128

x = 10

Son's age is 10 and fathers age is 4×10 = 40

Answer 2

Answer:

son age is 10

Father age is 40

Step-by-step explanation:

Let son's present age be x and fathers present age be 4x

8 yrs ago:

Son's age = x - 8

Fathers age = 4x-8

Also, Fathers age = 16(x-8)

4x -8 = 16x - 128

x = 10

Son's age is 10 and fathers age is 4×10 = 40