Question

A father's age is four times that of his son eight years before, the father's age was 16 times that of the son.father's age is:-​

Answer 1

Answer:

According to me the answer is '40'

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Let the age of the son :- x years

Then,

Age of the father = 4x years

Before 8 years,

Son's age = x - 8

Father's age = 4x - 8

4x - 8 = 16(x - 8)

= 4x - 8 = 16x - 128

= 12x = 120

= x = 10

Thus,

Father's age = 4 * 10 = 40 years

Hope it will help you

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