Math, asked by Charushrivandana, 9 months ago

A father's age is three times that of his son's age. Eight years ago, his age was 5 times that of his son. How old is the son at present?

Answers

Answered by MaIeficent
12

Step-by-step explanation:

\bf{\underline{\underline\red{Given:-}}}

  • The age of father is three times that of his son's age.

  • Eight years ago the age of father was 5 times that of his son.

\bf{\underline{\underline\blue{To\:Find:-}}}

  • The present age of son.

\bf{\underline{\underline\green{Solution:-}}}

According to the 1st condition :-

The age of father is three times that of his son's age.

Let the age of son be x

The age of father = 3x

According to the 2nd condition:-

Eight years ago, his age was 5 times that of his son.

Eight years ago:-

Age of son = x - 8

Age of father = 3x - 8

Age of father is 5 times that of his son.

→ 3x - 8 = 5( x - 8 )

→ 3x - 8 = 5x - 40

→ 3x - 5x = -40 + 8

→ -2x = -32

\rm x =  \dfrac{ - 32}{ - 2}

→ x = 16

The age of son = x = 16

Age of father

= 3x

= 3 × 16

= 48

\boxed{  \rm  \therefore Present \: age \: of \: son \:  = 16 \: years}

Answered by VaibhavTheAryabhatta
4

Step-by-step explanation:

☆ To Find,

》Son's age《

Solution:

☆ Let son's present age be x years

☆ Father's age = 3x years

☆ Now, Eight years before or ago

》Son's age= x-8 years

》Father's age= 3x-8 years

According to the question or ACQ,

5(x-8)=3x-8 [ Because Before 8 years

father was 5 times than that of his son, so

that 5 times of son's age is equal to father

age]

5x-40 = 3x-8

5x-3x=40-8 [By transporting]

2x=32

x=16

Clearly,

Ans; Son's age is 16 years

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