A father's age is three times that of his son's age. Eight years ago, his age was 5 times that of his son. How old is the son at present?
Answers
Answered by
12
Step-by-step explanation:
- The age of father is three times that of his son's age.
- Eight years ago the age of father was 5 times that of his son.
- The present age of son.
According to the 1st condition :-
The age of father is three times that of his son's age.
Let the age of son be x
The age of father = 3x
According to the 2nd condition:-
Eight years ago, his age was 5 times that of his son.
Eight years ago:-
Age of son = x - 8
Age of father = 3x - 8
Age of father is 5 times that of his son.
→ 3x - 8 = 5( x - 8 )
→ 3x - 8 = 5x - 40
→ 3x - 5x = -40 + 8
→ -2x = -32
→
→ x = 16
The age of son = x = 16
Age of father
= 3x
= 3 × 16
= 48
Answered by
4
Step-by-step explanation:
☆ To Find,
》Son's age《
Solution:
☆ Let son's present age be x years
☆ Father's age = 3x years
☆ Now, Eight years before or ago
》Son's age= x-8 years
》Father's age= 3x-8 years
♧According to the question or ACQ,
♤ 5(x-8)=3x-8 [ Because Before 8 years
father was 5 times than that of his son, so
that 5 times of son's age is equal to father
age]
♤ 5x-40 = 3x-8
♤ 5x-3x=40-8 [By transporting]
♤2x=32
♤x=16
☆Clearly,
Ans; ♡Son's age is 16 years♡
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