a father's age is three times the sum of Ages of his two sons five years later he will be twice the sum of the ages of his two sons find the present age of the father
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3
let the ages of two sons be X
and father age be Y
then
according to question
=》3 (X)=Y----------eq 1
x=y/3
then
2(X+10)=Y+5 {we take here x+10 because it is the age of two sons so 5×2=10}
=》 2x +20=Y+5
=》 2x -y+15=0 -------eq 2
by eq 1 and eq 2
2y/3-y+15=0
multiplying eq by 3
2y-3y+45=0
-y=-45
y=45
so age of father is 45
and father age be Y
then
according to question
=》3 (X)=Y----------eq 1
x=y/3
then
2(X+10)=Y+5 {we take here x+10 because it is the age of two sons so 5×2=10}
=》 2x +20=Y+5
=》 2x -y+15=0 -------eq 2
by eq 1 and eq 2
2y/3-y+15=0
multiplying eq by 3
2y-3y+45=0
-y=-45
y=45
so age of father is 45
Answered by
4
Answer:let the sum of his two son's age = x
then,father become =3x
5 year later age of son= x+5
and father = 3x+5
a/q
3x+5=2 (x+5)
3x+5=2x+10
3x-2x=10-5
x=5
sum of sons age =5
fathers age =15
Step-by-step explanation:
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