Question

A father's age is three times the sum of the ages of his two children. After 3
years his age will be two times the sum of their ages. Find the present age of
the father.​

Answer 1

Let the sum of the ages of the father's sons be x.

Father's age = 3x

After 3 years,

Sum of son's ages = x + 3

Father's age = 3x + 3

Now, the father's age is two times the sum of their ages.

= 3x + 3 = 2(x + 3)

= 3x + 3 = 2x + 6

= x = 3

The father's age is 9 years.

Answer 2

Answer:

27 years is age of Father .

Step-by-step explanation:

Let F be fathers age & c , c' represent ages of children , then :

F = 3(c+c') .....(1)

F + 3 = 2(c+c'+6)

F + 3 = 2[(F/3)+6] [from(1)]

3F + 9 = 2F + 36

F = 36 - 9 = 27