Question

A father’s age is three times the sum of the ages of his two children. After 5 years his age

will be two times the sum of their ages. Find the present age of the father.​

Answer 1

Answer:

Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5. Thus the age of the father is 45. Answer: A father's age is three times the age of his two sons.F

Answer 2

Question:

A father’s age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages. Find the present age of the father.

To find:

To find the present age of the father.

Answer:

$The \: father’s \: present \: age \: is \: \underline{ \: \underline{ \: \sf \pink{\bold{45}} \: } \: }$

Given:

• Father's present age is = 3(x+y)

$Let \: 3(x + y) \: be \: eq( 1 )$

• After 5 years their age will be, 2(x+5+y+5)

Step-by-step explanation:

Let his first son age be x and his second son age be y .

After 5 years their age will be, increased by 5

$\implies3(x + y) + 5 = 2(x + 5 + y + 5)$

$\implies3(x + y) + 5 = 2(x + y + 10)$

$\implies3x + 3y + 5 = 2x + 2y + 20$

$\implies3x - 2x + 3y - 2y = 20 - 5$

$\implies \boxed{ x + y = 15}$

Now substituting x + y = 15 in ( 1 )

$\implies3(15) =\boxed {45}$

$\therefore The \: father’s \: present \: age \: is \: \bold{45}$

Hint given in the question :

★ A father’s age is three times the sum of the ages of his two children.

★ After 5 years his age will be two times.

⚠️Note⚠️

Read the hint properly.

Because it forms the equation.