Question

A father’s age is thrice
the age of his Son. 10 years passed.
Now, father’s age is double the age of
his son.

Answer 1

Answer:

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Step-by-step explanation:

Step-by-step explanation:

\begin{gathered}a {}^{4} - 2a {}^{2} b {}^{2} + b {}^{4} = 0 \\ (a {}^{2} - b {}^{2} ) {}^{2} { = 0} \\ (a {}^{2} - b {}^{2} ) (a {}^{2} - b {}^{2} ) = 0\end{gathered}

a

4

−2a

2

b

2

+b

4

=0

(a

2

−b

2

)

2

=0

(a

2

−b

2

)(a

2

−b

2

)=0

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Mark me BRAINLIST please

Answer 2

Answer:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+10)+10=2[(x+10)+10]

⇒3x+20=2x+40

⇒x=20

∴ Required ratio =(3x+10):(x+10)=70:30=7:3

Step-by-step explanation:

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