A father's age is thrice the sum of ages of his two children. After 5 years his age will be twice
the sum of the ages of his two children. Find the present age of the father.
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Let the sum of two son's be “y” years.
Then father's age will be 3y,
After 5 years,
(y+5)=(3y+5),
But it is given that,
2 (y+5)=(3y+5),
2y +10=3y+5,
3y-2y=10+5,
y=15.
Hence,the father age is 15.
Then his son's age will be 2½ & 2½.
Anonymous:
thanks aisha ...!
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