A father's age is thrice the sum of ages of his two children. After 5 years his age will be twice the sum of the ages of his two children .Find their present age
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let father's present age be x years.
ley sum of his two children's ages be = y years
A.T.Q,
x=3y -(1)
after 5 years,
2(x+5)=2(y+5)
By (1)
2(3y+5)=2y+10
6y+10=2y+10
y=0
Hence , your question is wrong
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