Question

A father's age is twice his daughter's age but 16 years ago the father's age was
4 times his daughter's age. Calculate their ages.
Ulamancuch that Raheem​

Answer 1

Answer:

Let daughters age be x years

And father's age be 2x years

16 years ago

Daughters age = x-16

Father's age = 2x-16

A.t.q

4(x-16) = 2x-16

4x-64=2x-16

2x=48

X=24

Daughters age =24years

Father's age=48 years

Explanation: