Question

A father's age was four times and two times of his son at 2032 and 2050 respectively.find birth year of the son.​

Answer 1

Answer:

Let father age x.

Let son age y.

Now,

in the year of 2032

x=4y--->eeq(1)

in the year of 2050

it means after 18years

(x+18)=2(y+18) --->equ(2)

Substiting

4y+18=2y+36.

y=9.

Therefore the birth of his son,

2032-his present age 9.

= 2023