Math, asked by Saitama0011, 9 months ago

a father's is three time his son's age 10 year ago he was 5 times his son's age find their present age​

Answers

Answered by vatsalpatni
1

Answer:

Son's age = 20 years

Father's age = 60 years

Step-by-step explanation:

Let the age of father = f

and the age of son = s

10 years ago,

f - 10 = 5(s-10)

f -10 = 5s-50

f = 5s - 40. ----(1)

Present ages,

f = 3s. ----(2)

From (1) and (2),

3s = 5s - 40

5s - 3s = 40

2s = 40

s = 20 years

From (2),

f = 3s

f = 3(20)

f = 60 years

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