Math, asked by naziak27, 1 year ago

A father's present age is 4 times that of his son's present age. Ten years hence, father's age will be 3 times that of his son's age at that time. Find their present ages.

Answers

Answered by aashijain8
1

Answer:

father's age=4x

sons age...x

put the eq.

Answered by PixleyPanda
1

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20

Similar questions