Question

A father said to his son that his (father) age was 7 times his (son) age and his mothers age was 6 times his age 15 years before. If age of father is 5 years more than that of mother, then sum of their ages (all the three) at present will be

Answer 1

Answer:

Let the present age of father be 'x' and the present age of son be 'y'

then the present age of mother will be 'x-5'

X-15=7(y-15)

X-15=7y-105

X-7y= -90 __________(1)

(X-5-15)=6(y-15)

X-20=6y-90

X-6y= -70 ___________(2)

(2)-(1)

x-6y-(x-7y) = -70 - (-90)

X-6y-x+7y=20

Y=20

X-120= -80 ____ From (2)

X=40

Then the age of mother is 35

Then the sum of the ages of the three will be 20+40+35=95