Question

A father said to his son, "Two years ago I was three times as old as you; but in fourteen years I shall be only twice as old as you."​find the present age of father and son?

Answer 1

Answer:

present age of Father = 50 yrs, and of son is 18 yrs

Step-by-step explanation:

Let f be the father’s age and s be the son’s age.

Two years ago their ages would be f – 2 and s – 2, and the father was 3 times as old, so we have:

f – 2 = 3(s – 2)

f = 3s – 4

In 14 years their ages will be f + 14 and s + 14 and the father will be twice the age of the son, so we have:

f + 14 = 2(s + 14)

f = 2s + 14

These equations are equal to each other, so we have:

3s – 4 = 2s + 14

s = 18

f = 2s + 14

f = 50

The father is 50 and the son is 18.

Answer 2

Answer:

The father age - 50 years & son age - 18 years old