Question

A father  says to his son, "7 years ago, I was 7 times as old as you were and after 3 years ,I will be 3 times as old as you will be". Find their present ages.

Answer 1

Answer:

42 years and 12 years

Step-by-step explanation:

Let father's present age = x years

and son's present age = y years

According to the first condition:x − 7 = 7 (y − 7)⇒ x − 7 = 7y − 49⇒ x − 7y = −49 + 7⇒ x − 7y = −42  ...........(1)

According to the second condition:x + 3 = 3 (y + 3)⇒ x + 3 = 3y + 9⇒ x − 3y = 9 − 3⇒ x − 3y = 6  ...........(2)

Subtracting (1) from (2) we get,

4y = 48⇒ y = 48/4 = 12

Putting the value of y in (1) we get,x − 7 × 12 = −42⇒ x − 84 = −42⇒ x = −42 + 84⇒ x = 42

Hence father's age is 42 years and son's present age is 12 years.

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