Question

a father speak his child at 3:30 PM from school. one day left at 2:30 p.m. instructed the work at speed 6 kilometre per hour and there is the home 24 minutes earlier. find the speed of father.
please give me the answer I need immediately I give hundred points. please give me the answer.

Answer 1

Distance is inversely proportional to time,
T1/T2= 1/24min
No change the value of time into seconds, 24×60 = 1440
T1= 60×60=3600
T1/T2= 3600/1440
S1/S2= T2/T1
Initially the speed, S1 = 6 km/h
S1= 6×5/18 = 30/18
30/18S2= 1440 /3600
30/8S2= 1440/3600
1/18S2= 0.4
18S2= 10/4
S2= 10/18×4
S2= 0.13 m/s