Question

A father was 21 years older than his son three years backc At present the father is 4 times as old as his son. How old will he son be five years from now?​

Answer 1

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Answer 2

Given,

A father was $\[21\]$years older than his son three years back.

At present, the father is $\[4\]$ times as old as his son.

Solution,

Assume that the present age of father and son be $\[x\,{\rm{and}}\,y\]$ respectively.

Therefore,

$\[ \Rightarrow x = 4y - - - - \left( 1 \right)\]$

So,

$\[\begin{array}{l} \Rightarrow \left( {x - 3} \right) - 21 = y - 3\\ \Rightarrow x - 24 = y - 3\end{array}\]$

Apply equation (1),

$\[\begin{array}{l} \Rightarrow 4y - 24 = y - 3\\ \Rightarrow 4y - y = 24 - 3\\ \Rightarrow 3y = 21\\ \Rightarrow y = 7\end{array}\]$

Therefore, the age of the son after five years

$\[\begin{array}{l} \Rightarrow 7 + 5\\ \Rightarrow 12\end{array}\]$

Hence, the age of the son after five years is $\[12.\]$